√(6+2√(7+3√(8+...))) = 4
Last updated
Was this helpful?
Last updated
Was this helpful?
參考:
Math Stack Exchange: Prove: = √(6+2√(7+3√(8+...))) = 4
Math Stack Exchange: What is the value of √(1+2√(2+3√(3+...)))?
Desmos: √(6+2√(7+3√(8+...))) = 4
Wikipedia: [Ramanujan's Infinite Radicals]([[https://en.wikipedia.org/wiki/Nested_radical#Ramanujan's_infinite_radicals](https://en.wikipedia.org/wiki/Nested_radical#Ramanujan's_infinite_radicals)](https://en.wikipedia.org/wiki/Nested_radical#Ramanujan's_infinite_radicals]%28https://en.wikipedia.org/wiki/Nested_radical#Ramanujan's_infinite_radicals%29)\)